A researcher investigated the number of days patients spend at a hospital. Patie

Question

A researcher investigated the number of days patients spend at a hospital. Patients were randomly selected from four regions and the number of days each patient spent at a hospital was recorded. The accompanying table shows he results AL a = 005, can the researcher reject the claim that the mean number of days patients spend in the hospital is the same for all four regions? Perform a one way ANOVA lost by completing parts a through d. Assume that each sample is drawn from a normal population, that the samples are independent of each other and that the populations have the same variances. The critical value is F_o (Round two decimal places as needed.) The rejection region is F (Round two decimal places as needed) (c) Calculate the test statistic. F = (Round to three decimal places as needed) (d) Decide to rejecter to reject the null hypothesis and interpret the decision in the context of the original claim. Choose the correct decision below. A. Since F is not in the election region reject H_0 B. Since F is in the rejection region fall to reject H_0 C. Since F is not in the rejection region. fall to reject H_0 D. Since F is in the rejection region reject H_0. Interpret the decision in the context of the original claim. There enough evidence at the 5% significance level to the claim that the mean number of days patents spend in the hospital is

Explanation / Answer

applying one way ANOVA on above:

from above: F critical=3.20

rejection region F>3.20

c)F=0.241

d) option C is correct

there is not enough................to reject the claim..............is different

Groups Count Sum Average Variance north 6 33 5.5 5.1 east 6 31 5.166667 2.166667 south 4 20 5 2 west 5 23 4.6 2.8 ANOVA Source of Variation SS df MS F P-value F crit Between Groups 2.27619 3 0.75873 0.240942 0.866568 3.196777 Within Groups 53.53333 17 3.14902 Total 55.80952 20

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