A researcher studying salaries of police officers around the nation surveyed 64

Question

A researcher studying salaries of police officers around the nation surveyed 64 officers and found a mean salary of $71,228 with a standard deviation of $7,425. Make a 99% confidence interval for the mean salary of all police officers. A researcher studying salaries of police officers around the nation surveyed 64 officers and found a mean salary of $71,228 with a standard deviation of $7,425. Make a 99% confidence interval for the mean salary of all police officers. A researcher studying salaries of police officers around the nation surveyed 64 officers and found a mean salary of $71,228 with a standard deviation of $7,425. Make a 99% confidence interval for the mean salary of all police officers.

Explanation / Answer

Solution:-

A researcher studying salaries of police officers around the nation surveyed 64 officers and found a mean salary of $71,228 with a standard deviation of $7,425. Make a 99% confidence interval for the mean salary of all police officers.

If (n 30)

Confidence Interval = xbar ± z/2 × (n)

Where,

x = Sample Mean = 71,228

= Standard Deviation = 7,425

= 1 - (Confidence Level / 100) = 0.01

Putting the given values in the above equation, we get

xbar ± z/2 × (n)

= 71,228 + 2.58 x (7,425 / 64 )

= 71,228 + 2.58 x 928.125

confidence interval for the mean salary of all police officers = 68833.438 < µ < 73622.563

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