Question Hep A study of a new methodology tested This table shows how students u
ID: 3232496 • Letter: Q
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Question Hep A study of a new methodology tested This table shows how students using the new method and me traitonalmemod performed What do you conclude? (Assume the conditions for inference met Assume a significance level of 0.10) Math Program SD 267 538 286 Identify the null and altemative hypotheses. Choose the comect ansaer below Pr 0 Compute the test statistic (Round to two decimal places as needed) Find the P value The P-value is (Round to three decimal places as needed State the conclusion Choose the correct answer below O A. Reyect the null is sufficient evidence taught using the new method O B Falto typothesis There is not sufmcient evidence thar st masto mean score on the word problems than traditional student method have a mean on the problms est tan taught using sufficient evidence mat students method have a dnerert mean score on the word pottees test than Made snude ts method have a mean score on the word problems test than adtoalstuse cat k to select your answer (s)Explanation / Answer
Solution:-
State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.
Null hypothesis: 1 - 2 = 0
Alternative hypothesis: 1 - 2 0
Note that these hypotheses constitute a two-tailed test. The null hypothesis will be rejected if the difference between sample means is too big or if it is too small.
Formulate an analysis plan. For this analysis, the significance level is 0.10. Using sample data, we will conduct a two-sample t-test of the null hypothesis.
Analyze sample data. Using sample data, we compute the standard error (SE), degrees of freedom (DF), and the t statistic test statistic (t).
SE = sqrt[(s12/n1) + (s22/n2)]
SE = 2.50
DF = 592
t = [ (x1 - x2) - d ] / SE
t = 1.24
where s1 is the standard deviation of sample 1, s2 is the standard deviation of sample 2, n1 is the size of sample 1, n2 is the size of sample 2, x1 is the mean of sample 1, x2 is the mean of sample 2, d is the hypothesized difference between the population means, and SE is the standard error.
Since we have a two-tailed test, the P-value is the probability that a t statistic having 40 degrees of freedom is more extreme than -1.24; that is, less than -1.24 or greater than 1.24.
Thus, the P-value = 0.2155
Interpret results. Since the P-value (0.2155) is greater than the significance level (0.10), we have to accept the null hypothesis.
Fail to reject the null hypothesis, there is not sufficient evidence that students taught using new methods have different scores on the word problem test than the old method.
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