The time (in hours) that a technician requires to preform preventive maintenance
ID: 3232606 • Letter: T
Question
The time (in hours) that a technician requires to preform preventive maintenance on an air-conditioning unit has a mean of 1 hour and a standard deviation of 1 hour Suppose your company has a contract to maintain 70 of these units in an apartment building. You must schedule technicians' time for a visit to this building and develop a budget. Is it safe to budget an average of 1.1 hours for each unit? Or should you budget an average of 1.25 hours? A random sample of 92 adults is selected from the city of Whitewater and it is found that 61 have health insurance a. Give an estimate for the true proportion of all adults in Whitewater who have health insurance Specify- the probability distribution for this estimate. b. Find a 95% confidence interval for the true proportion of all adults in the town who have health insurance. What does this interval tell you? Suppose the City of Whitewater wishes to test the belief (hypothesis) that the proportion of all adults in Whitewater who have health insurance is 80%, or P = 0.80. Is the City of Whitewater justified in this belief? Why or why not? You must base your answer on evidenceExplanation / Answer
32)
(A) estimate of true proportion, pcap = 61/92 = 0.663
The probability distribution of the estimate is approximately normal.
B) For 95% CI, z-value = 1.96
Standard error = sqrt(0.663*(1-0.663)/92) = 0.0493
Margin of error = 1.96*0.0493 = 0.0966
confidence interval = (0.663 - 0.0966, 0.663 + 0.0966) = (0.5665, 0.7596)
The above CI indicates that 95% of chance that a sample 92 has proportion of adults having health insurance is between the CI of (0.5665, 0.7596)
C)
As the value of hypothesised proportion does not fall withing confidence interval, we reject the null hypothesis. This means there are sufficient evidence to conclude that proportion adults having health insurance is not equal to 0.8.
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