Assume a binomial probability distribution. Forty percent of the population has

Question

Assume a binomial probability distribution. Forty percent of the population has brown eyes. If 14 people are randomly selected, find the probability that at most 2 of them have brown eyes. a. 0.0390 b. 0.0317 c. 0.0398 d. 0.0073 e. 0.0008 In a standard normal distribution, find the area that is less than z = 1.43: a. 0.0764 b. 0.3570 c. 0.4236 d. 0.9236 e. None of these. In a standard normal distribution, find the area that is greater than z = -2.13: a. .5166 b. .0166 c. .9834 d. .4834 e. None of these. Assume values are normally distributed with a mean of 10 and a standard deviation of 2. The probability that a randomly selected value lies between 7 and 9 is: a. 0.6247 b. 0.3085 c. 0.2417 d. 0.0668 e. None of these. Use the normal distribution to approximate the desired binomial probability. Merta reports that 74% of its trains are on time. A check of 60 randomly selected trains shows that 38 of them arrived on time. Find the probability that among the 60 trains, 38 or fewer arrive on time. Based on the result, would it be unusual for 38 or fewer trains to arrive on time? a. 0.032, yes b. 0.032, no c. 0.041, yes d. 0.041, no Find the percentage of z scores that lie between z = -1.31 and z = 1.86 in a standard normal distribution. a. 6.37% b. 40.49% c. 46.86% d. 87.35%

Explanation / Answer

Solution:-

44) (c) The probability that atmost two have brown eyes is 0.0398.

p = 40/100

p = 0.40

n = 14

By applying binomial distribution:-

P(x, n, p) = nCx*p x *(1 - p)(n - x)

P(x < 2) = 0.0398

The probability that atmost two have brown eyes is 0.0398.

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