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As reported distributed in \'Runner\'s World\" magazine, the times of the finish

ID: 3236053 • Letter: A

Question

As reported distributed in 'Runner's World" magazine, the times of the finishers in the New York City 10 km run are normally distributed with mu = 61 minutes and sigma = 9 minutes. Let X denote finishing time for the finishers. The percentage of finishers with times between 60 and 90 minutes is equal to the area under the standard normal curve between 0.1111 and 3.2222 The percentage of finishers with times exceeding 84 minutes is equal to the area under the standard normal curve that lies to the of 2.5555

Explanation / Answer

a)

Z1 = (60 - 61) / 9 = -1/9 = -0.1111

Z2 = (90 - 61) / 9 = 29/9 = 3.2222

The percentage of finishers with times between 60 and 90 minutes is equal to the area under the standard normal curve between -0.1111 and 3.2222

b)

Z = (84 - 61) / 9 = 23/9 = 2.5556

The percentage of finishers with times exceeding 84 minutes is equal to the area under the standard normal curve that lies to the ..........of 2.5556