Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Problem 3. (15 points) We want to study the distribution of sleep deprivation fo

ID: 3236738 • Letter: P

Question

Problem 3. (15 points) We want to study the distribution of sleep deprivation for people affected by 3 distinct diseases. Random samples of affected subjects of sizes 80, 70 and 60 from disease 1, 2 and 3, respectively were obtained. The results are shown in the following table.

Very severe

Severe

Mild

None

Disease 1

10

7

30

33

80

Disease 2

7

13

20

30

70

Disease 3

5

6

15

34

60

For all subsequent parts state the null and alternative hypothesis, write down the test statistics and their degrees of freedom, calculate the test statistics, find the p-values and give interpretations.

(5 points) Test the hypothesis that the proportions of subjects affected by Disease 3 that experience very severe, severe, mild and no sleep deprivation are (0.1, 0.1, 0.3, 0.5) (i.e the distribution of sleep deprivation for subjects affected by Disease 3 is multinomial with probabilities (0.1, 0.1, 0.3, 0.5)). Use R to confirm your result (need chisq.test() command).

(5 points) Test the hypothesis that the proportions of subjects that experience very severe, severe, mild and no sleep deprivation are (0.1, 0.1, 0.3, 0.5) for all three diseases (i.e. the distributions of sleep deprivation are completely specified multinomial with probabilities (0.1, 0.1, 0.3, 0.5)).

(5 points) Test the hypothesis that the proportions of subjects that experience very severe, severe, mild and no sleep deprivation are the same for all three diseases (i.e the distributions of sleep deprivation are multinomial with the same unspecified probabilities).

Very severe

Severe

Mild

None

Disease 1

10

7

30

33

80

Disease 2

7

13

20

30

70

Disease 3

5

6

15

34

60

Explanation / Answer

Ho:sleep deprivation for people is not assosiated with distinct diseases.

Ho:sleep deprivation for people is assosiated with distinct diseases.

       A      B      C      D

1     10      7     30     33     80

2      7     13     20     30     70

3      5      6     15     34     60

      22     26     65     97    210

expected: contingency table

        A          B          C          D

1    8.38       9.90       24.8       37.0   

2    7.33       8.67       21.7       32.3   

3    6.29       7.43       18.6       27.7   

chi-square = 7.82
degrees of freedom = 6
probability = 0.251

CONCLUSION :sleep deprivation for people is not assosiated with distinct 3 diseases P=0.251 (P>0.05)

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote