In an early home game, an NBA team made 66.67 percent of their 93 free throw att
ID: 3237171 • Letter: I
Question
In an early home game, an NBA team made 66.67 percent of their 93 free throw attempts. In one of their last home games, the team had a free throw percentage equal to 77.91 percent out of 86 attempts. Do basketball teams improve their free throw percentage as their season progresses? Test the hypothesis of equal free throw percentages, treating the early season and late season games as random samples. Use a level of significance of .10.
Calculate the Z test statistic value. (Round your answer to 4 decimal places. Negative value should be indicated by a minus sign.)
In an early home game, an NBA team made 66.67 percent of their 93 free throw attempts. In one of their last home games, the team had a free throw percentage equal to 77.91 percent out of 86 attempts. Do basketball teams improve their free throw percentage as their season progresses? Test the hypothesis of equal free throw percentages, treating the early season and late season games as random samples. Use a level of significance of .10.
(a-3)Calculate the Z test statistic value. (Round your answer to 4 decimal places. Negative value should be indicated by a minus sign.)
Z test statistic valueExplanation / Answer
p1 = 66.67 = 0.6667 , n1 = 93 , p2 = 77.91 = 0.7791 , n2 = 86
s1 = sqrt(n1 * p1 * q1) = 4.5459
s2 = sqrt(n2 * p2 * q2) = 3.8472
x1 = n1 * p1 = 93 * 0.6667 = 62.0031
x2 = n2 * p2 = 86 * 0.7791 = 67.0026
SE = sqrt[(s1^2/n1) + (s2^2/n2)]
SE = sqrt[(4.5459^2/93) + (3.8472^2/86)]
= 0.6279
z = (x1 - x2) / SE
= ( 62.0031 - 67.0026) / 0.6279
= -7.9623
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