Please help with both, I\'m not sure what to do. Some people seem to believe tha

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Please help with both, I'm not sure what to do.

Some people seem to believe that you can fix anything with duct tape. Even so, many were skeptical when researchers announced that duct tape may be a more effective and less painful alternative than liquid nitrogen, which doctors routinely use to freeze war An article described a study conducted at a medical cen Patients with warts were randomly assigned to either the duct tape treatment or the more traditional freezing treatment. Those in the duct tape group wore duct tape over the wart for 6 days, then removed the tape, soaked the area in water, and used an emery board to scrape the area. This process was repeated for a maximum of 2 months or until the wart was gone. Data consistent with values in the article are summarized in the following table. Number with Wart Treatment Successfully Removed Liquid nitrogen freezing 104 60 Duct Tape 103 88 Do these data suggest that freezing is less successful than duct tape in removing warts? Test the relevant hypotheses using a significance level of 0.01. (Use a statistical computer package to calculate the P-value. Use unitrogen uduct tape. Round your test statistic to two decimal places and your P-value to four decimal places.) P-value

Explanation / Answer

a)
Hypothesis:
H0 : p1 = p2
Ha : p1 < p2

Data:

n1 = 104 , p1 = 60/104 = 0.577 , q1 = 1 -p1 = 1 - 0.577 = 0.423
n2 = 103 , p2 = 88/103 = 0.854 , q2 = 0.146

Test tatistic:

p = (p1 * n1 + p2 * n2) / (n1 + n2)
= ( 0.577 * 104 + 0.854 * 103) / ( 104 + 103)
= 0.7149

SE = sqrt{ p * ( 1 - p ) * [ (1/n1) + (1/n2) ] }
= sqrt { 0.7149 * ( 1 -0.7149) * (1/104 + 1/103)}
= 0.0627
z = (p1 - p2) / SE
= ( 0.577 - 0.854) / 0.0627
= -4.425

p value is calculated using z = -4.425
P value = 0.00001.

Conclusion:
We reject the null hypothesis
These data suggest that freezing is less successful than duct tape in removing warts

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