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A group against drunk driving did a recent study and found the above information

ID: 3238402 • Letter: A

Question

A group against drunk driving did a recent study and found the above information regarding 400 that occurred on a Saturday night in NY. What is the probability of accidents involving a single given that alcohol was involved? a. 50/75 b. 50/170 c. 120/170 d. 120 400 To conduct a research project on college student income, the number of student to sample needs to To estimate the mean population income, we decide to use a 1% level of signification The standard deviation from other studies of student income is $1 500. Referring to Problem C. using a 1% level of significance, the critical value is a. 1.96 b. 1.64 c. 0.005 d. 1.00 Referring to Problem C, what sample size is required? a. 20 b. 1 c. 217 d. 152 A multiple-choice test has 30 questions. There are 4 choices for each question. A study studied for the test decides to answer all questions randomly. What type of probability di: used to figure out his chance of getting at least 20 questions right? a. Binomial distribution b. Normal distribution C. Standardized normal distribution d. None of the above Two normal distributions are compared. One has a mean of 10 and a standard deviation of normal distribution has a mean of 10 and a standard deviation of 2. Which of the following a. the locations of the distributions are different b. the distributions are from two different families c. the dispersions of the distributions are different d. the dispersions of the distributions are the same. An insurance company needs to assess the risks associated with providing hurricane average number of tropical storms or hurricanes that hit Florida is 2 per independent, and the data follows a Poisson distribution, what is the probability of with no hurricanes? a. 0 b. A total of 1 C. 27.4% d. 13.5%

Explanation / Answer

P(X>=20) = ?

It is .25 probability that the question will answered rightly.

P(X>=20) = 30C0 (.25^0)(.75^30) + ... + 30C30 (.25^30)(.75^0)

This is the binomial distribution at work.

So, the answer is A

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