The mean daily production of a herd of cows is assumed to be normally distribute

A) P(X 33.2) = P(z > (33.2 - 37)/4.7) = P(z > -0.81) = 0.7906

ID: 3241549 • Letter: T

Question

The mean daily production of a herd of cows is assumed to be normally distributed with a mean of 37 liters, and standard deviation of 4.7 liters.

A) What is the probability that daily production is less than 28.5 liters?

Answer= (Round your answer to 4 decimal places.)

B) What is the probability that daily production is more than 33.2 liters?

Answer= (Round your answer to 4 decimal places.)

Warning: Do not use the Z Normal Tables...they may not be accurate enough since WAMAP may look for more accuracy than comes from the table.

A) P(X < 28.5)

= P(z < (28.5 - 37)/4.7)

= P(z < -1.81)

= 0.0353

B) P(X > 33.2)

= P(z > (33.2 - 37)/4.7)

= P(z > -0.81)

= 0.7906

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