please show all workings 2. A committee of 6 people, which must contain at least
ID: 3241571 • Letter: P
Question
please show all workings
Explanation / Answer
(i)
Total number of members : 10+9=19
There are 10 women and 9 men. Number of ways of selecting 4 men out of 10 men is
C(10,4) = 210
Number of ways of selecting 1 woman out of 9 women is
C(9,1) = 9
After selecting 4 men and 1 woman number of members remaining is 19 -5 = 14. Number of ways of selecting 1 member out of 14 is C(14,1)=14.
So number of ways of selecting 6 members such that at least 4 are men and 1 is woman is
210* 9 * 14 = 26,460
(ii)
Number of ways of selecting Anil and Stacy is 1. After that number of ways of selecting at least 3 men is
C(8,3) C(14,1) = 784
(iii)
Let us first find the number of committees that include only Anil not Stacy. After selecting Anil number of men remaining is 9 and since Stacy is not in the committee so number of women remaning is 8. So possible number of committees inlcuding Anil only is
C(9,3)C(8,1)C(13,1) = 8736
Likewise possible number of committees inlcuding Stacy only is
C(9,4)C(13,1) = 1638
SO number of poissble commitees including either Anil or Stacy but not both is 8736+1638 = 10374
(iv)
Total number of possible arrangements of 6 people is 6! = 720
Let women are together so number of ways arranging 5 persons in a line is 5! = 120 and two women can arrange themselves in 2!=2 ways. So possible line ups in which women are together is 120*2 = 240
So possible number of line ups in which women are not together is 720 - 240 = 480
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