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2. According to Center for Disease Control and Prevention (http://www.cdc.gov/),

ID: 3242809 • Letter: 2

Question

2. According to Center for Disease Control and Prevention (http://www.cdc.gov/), the mean
length of a six-month old American girls is about 65.73 cm and the standard deviation is
about 2.27 cm.

(a) Find the 5th percentile and the 95th percentile.

(b) A simple random sample of 50 six-month old girls’s growth records were selected from a
certain city. Assuming that this city’s environment is not different from the national average,
find the 5th and the 95th percentiles for the probability distribution of the sample mean.

Explanation / Answer

a) The Standard Normal Variate is Z = (X - Mean) / SD

gvien mean = 65.73 and sd = 2.2.7

From the standard norma table, Z5% = -1.645

The 5th percentile is X = Mean + Z5% * SD

= 65.73 -1.645*2.27 = 61.996

From the standard norma table, Z95% = 1.645

The 95th percentile is X = Mean + Z95% * SD

= 65.73 +1.645*2.27 = 69.464

b) Given sample size n = 50

The 5th percentile is X = Mean - Z5% * (SD / sqrt(n) )

= 65.73 -1.645* (2.27 / sqrt(50)) = 65.202

From the standard norma table, Z95% = 1.645

The 95th percentile is X = Mean + Z5% * (SD / sqrt(n) )

= 65.73 + 1.645* (2.27 / sqrt(50)) = 66.258