The amount of time (in seconds) needed to complete a critical task on an assembl

Question

The amount of time (in seconds) needed to complete a critical task on an assembly line was measured for a sample of 50 assemblies. These data are as follows: Draw a stem- and-leaf display Construct a frequency table using 7 classes Draw a box plot Detect any outliers The professors at Wilfrid Laurier University are required to submit their final exams to the registrar's office 10 days before the end of the semester. The exam coordinator sampled 20 professors and recorded the number of days before the final exam that each submitted his or her exam. The results were as follows: Compute the mean median, and mode Find the range, and compute the standard deviation Compute the Inter-Quartile range for these data The following data are direct solar intensity measurements (watts/m^2) on different days at a location in southern Spain: exist62, 869, 708, 775, 775, 704, 809, 856, 655, 806, 878, 909, 918, 558, 768, 870, 918, 940, 946, 661, 820, 898, 935, 952, 957, 693, 835, 905, 939, 955, 960, 498, 653, 730, 753. Calculate the sample mean, and the ample standard deviation. Following deregulation of telephone service, several new companies were created to compete in the business of providing long-distance telephone almost all cases these companies competed on price since the service each offered is similar. The company's marketing manager conducted a survey of 36 new residential subscribers wherein the first month's bill were recorded. These data are listed below. Compute the sample mean and sample standard deviation Calculate the median, the quartiles and the IOR Construct a box plot of the data and detect the possible presence of outliers

Explanation / Answer

Question 4)

1)
mean = sum of all numbers/ total numbers
= 160/20
= 8

median is the middle number
median = (8+9)/2 = 8.5

mode is the number which is more repeated
mode is 4

2)
Range = (largest - smallest)number
= ( 15 - 0)
= 15

Standard deviation = summation of ( x - mean)^2 / n
= 4.078

3)
Put them in order:
0 , 2 , 4 , 4, 4 , 5 , 6 , 6 , 7 , 8 , 9 , 9, 10 , 10 , 11, 12 ,12 , 13 , 13 , 15

Cut it into quarters;

0 , 2 , 4 , 4, 4 | 5 , 6 , 6 , 7 , 8 | 9 , 9, 10 , 10 , 11 | 12 ,12 , 13 , 13 , 15

In this case all the quartiles are between numbers:

Quartile 1 (Q1) = (4+5)/2 = 4.5
Quartile 2 (Q2) = (8+9)/2 = 8.5
Quartile 3 (Q3) = (11+12)/2 = 11.5

IQR = Q3 - Q1 = 11.5 - 4.5 = 7

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