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A bag comtains 20 marbles: 5 yellow, 2 white, 3 blue, and 10 green. if 4 are sel

ID: 3244638 • Letter: A

Question


A bag comtains 20 marbles: 5 yellow, 2 white, 3 blue, and 10 green. if 4 are selected at random, find the probability that the that a) 2 are yellow, with replacement, b) 2 are yellow without replacement, c) all are green, with replacement, e) there is one of each color,with replacement, f) there is one of each color without replacement, g) both white are taken, with replacement, and h) both whites are taken, without replacement.

Normal No Spac.. Heading1 Heading 2 Trtle Subtitle Subtle Em... Emphasis ipboard Paragraph Styles 5. A bag contains 20 marbles: 5 y bag contains 20 marbles: 5 yellow, 2 white, 3 blue, and 10 green. If 4 are selected at random, find the probability that ellow, 2 white, 3 blue, and 10 green. If 4 are selected at random, find the 5. A a. 2 are yellow, with replacement- b. 2 are yellow, without replacement All are green, with replacement All are green, without replacement There is one of each color, with replacement c. d. e. f. There is one of each color, without replacement g. Both whites are taken, with replacement of 3 763 words E

Explanation / Answer

A) P(2 are yellow, with replacement) = 4C2 x 5/20 x 5/20 x 15/20 x 15/20 = 0.2109

B) P(2 are yellow, withour replacement) = 4C2 x 5/20 x 4/19 x 15/18 x 14/17 = 0.2167

C) P(all are green, with replacement) = 10/20 x 10/20 x 10/20 x 10/20 = 0.0625

E) P(one of each color, with replacement) = 5/20 x 2/20 x 3/20 x 10/20 x 4! = 0.045

F) P(one of each color, without replacement) = 5/20 x 2/19 x 3/18 x 10/17 x 4! = 0.0619

G) P(both white are taken, with replacement) = 2/20 x 2/20 x 18/20 x 18/20 x 4C2 = 0.0486

H) P(both white are take, without replacement) = 2/20 x 1/19 x 18/18 x 17/17 x 4! = 0.0316

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