(1) Assume that the 26 letters of English language alphabet (A through Z) are th
ID: 3245376 • Letter: #
Question
(1)Assume that the 26 letters of English language alphabet (A through Z) are the equally likely outcomes (simple events) of a statistical experiment, e.g., a wheel of fortune with 26 equal divisions (wedges of the same central angle size), each labeled a unique letter. The 26 different equally probable outcomes comprise the sample space S.
If we conduct the statistical experiment once (e.g., rotating the wheel introduced above),
Name: Sascha
Last Name: Fitness
(a) The probability of getting a letter that can be found in your last name.
(b) The probability of getting a letter that can be found in your first and last names.
(c) The probability of getting a letter that can be found neither in your first name nor in your last name.
(d) If we conduct the statistical experiment twice, what is the probability that we once get a letter that exists in your complete name?
Explanation / Answer
a)
number of unique alphabets in lastname = 6
required probability = 6/26 = 3/13
b)
number of unique alphabets in lastname and firstname = 9
probability = 9/26
d)
probability = 1 -9/26 = 17/26
e)
required probability = 9/26 * 17/26 = 153/676
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