ons uc a scatter 1 t find he value o ne near correlation coet en r and find the

Question

ons uc a scatter 1 t find he value o ne near correlation coet en r and find the P-value using 0 05 s here su cient evidence to conclude The data below shows the high temperatures and the t es in minutes runners who won a marathon there is a linear corelation between temperature and winning times? at 63 54 59 Tme 148 079 146 603 145,751 146 588 What are the null and altemative hypotheses? Construct the scatterplot. Choose the correct graph below O C. D. 140 50 50 100 50 50 100 The inear correlation coefficient r is

Explanation / Answer

the linear correlation coefficient is    r = 0.5047

X Values
= 488
Mean = 61
(X - Mx)2 = SSx = 456

Y Values
= 1173.75
Mean = 146.719
(Y - My)2 = SSy = 11.53

X and Y Combined
N = 8
(X - Mx)(Y - My) = 36.594

R Calculation
r = ((X - My)(Y - Mx)) / ((SSx)(SSy))

r = 36.594 / ((456)(11.53)) = 0.5047

Meta Numerics (cross-check)
r = 0.5047

test statistic = r* sqrt (n-2)/ sqrt (1-r^2)

                 sustitute those values

                    =1.432022381

                    =1.432

The P-Value is .202111.      =0.202

The result is not significant at p < .05

the p-value is greater than alpha (p > .05), then we fail to reject the null hypothesis

   accept H0: P=0

THERE IS LINEAR RELATION BBETWEEN THEM

   YES BECAUSE THERE IS LINEAR RELATION BBETWEEN THEM

Related Questions

Navigate

• Browse (All)
• Browse O
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.