Each of two parents has the genotype brown/blue, which consists of the pair of a

Question

Each of two parents has the genotype brown/blue, which consists of the pair of alleles that determine eye color, and each parent contributes one of those alleles to a child. Assume that if the child has at least one brown allele, that color will dominate and the child's eye color will be brown. a. List the differed possible outcomes Assume that those outcomes are equally likely. b. What is the probability that a child of these parents will have the blue/blue genotype? c. What is the probability that the child will have brown eye color? a. List the possible outcomes. A. brown/brown, brown/blue, and blue/blue B. brown/blue and blue/brown C. brown/brown and blue/blue D. brown/brown, brown/blue, blue/brown and blue/blue b. The probability that a child of these parents will have the blue/blue genotype is. (Round to two decimal places as needed.) c. The probability that the child will have brown eye color is (Round to two decimal places as needed.)

Explanation / Answer

Solution:-
a. option D. brown/brown,brown/blue,blue/brown,blue/blue.

b.
1/4 = 0.25

The probability that a child of these parants will have the blue/blue genotype is 0.25

c. 3/4 = 0.75

The probability that the child will have brown eye color is 0.75

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