The U.S. Army requires women\'s heights to between 58 in. and 75 in. Women\'s he

Question

The U.S. Army requires women's heights to between 58 in. and 75 in. Women's heights (in USA) are normally distributed with a mean of 63.8 in. and a standard deviation of 2.6 in. Step 1: Determine the 2 scores for each of the Army women's height requirements (58" & 75"). Use Excel, fx, Statistical, and STANDARDIZE option to determine the z score. Z (58")= Z(75") = Step 2: Determine the probability of finding each women's height using Excel, fx, Statistical, NORM DIST.(x = 58, x = 63.8, s = 2.6, cumulative = 1) P(58") = P(75") =. Step 3: Determine the percentage of women meeting the height requirements of the U.S. Army P(75") -P(58") =. Step 4: Are many women being denied the opportunity to join the Army because they are too short or tall? Yes or No? Part B: The Boeing 757 doorway is 72 inches. Men's heights are normally distributed with a mean of 69.0 inches and a standard deviation of 2.8 inches. Women's heights are normally distributed with a mean of 63.8 in. and a standard deviation of 2.6 in. Step 1: Determine the z scores for men and women at a height of 72". Use Excel, fx, Statistical, and STANDARDIZE option to determine the z-score. Z (men) = Z(women) = Step 2: What percentage of men women can fit through the doorway without bending? Use Excel, fx, Statistical, NORMDIST (cumulative = 1) to determine the probability. P(men) = (women) = Step 3: Determine the percentage of men and women too tall to fit through a standard doorway. % men too tall % women too tall Step 4: Are there many men or women too tall to fit through a typical aircraft doorway? Yes or No?

Explanation / Answer

z=(X-mean)/sd=(X-63.8)/2.6

step1. for X=58, z=(58-63.8)/2.6=-2.23

for X=75, z=(75-63.8)/2.6=4.31

Step2.P(58)=0.0128, P(75)=0.9999

step3.P(75)-P(58)=0.9999-0.128=0.872

step.No. , as 87.2% were allowed only 12.8% are denied

Part(B)

step1, Z(men)=(72-69)/2.9=1.0344

Z(women)=(72-63.8)/2.6=3.1538

step2:P(men)=0.8495=84.95%, P(women)-0.9992=99.92%

step3:%of men=100-84.95=15.05

%women=100-99.92=0.08%

step4. yes,

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.