Recently the habit of overbooking on flights has become an issue. Airlines do ov
ID: 3248618 • Letter: R
Question
Recently the habit of overbooking on flights has become an issue. Airlines do overbooking since they have data on how often booked passengers will not arrive on time to take their flights. The probability that people who are overbooked will actually get a seat on the plane is found to be 69%. Your flight has 6 overbooked passengers and you are number 4. What is the probability that 4 out of the 6 overbooked passengers will actually get on the plane? (Since you are the 4th, will you take the offer of $1,000 and a later flight to not travel on this one?
Explanation / Answer
This is a case of binomial distribution and here we know that n is 6 and r is 4. We also know that P=0.69
Thus the answer is 6C4*(0.69)^4*(0.31)^2
Solving the above we get 0.3267
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