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REGRESSION /MISSING LISTWISE /STATISTICS COEFF OUTS CI(95) R ANOVA /CRITERIA=PIN

ID: 3248745 • Letter: R

Question

REGRESSION

/MISSING LISTWISE

/STATISTICS COEFF OUTS CI(95) R ANOVA

/CRITERIA=PIN(.05) POUT(.10)

/NOORIGIN

/DEPENDENT StartDate

/METHOD=ENTER Q17 Q18 Q19.

Variables Entered/Removeda          

Model   Variables Entered   Variables Removed   Method

1   Current job category, Tell us about yourself, Age groupb   .   Enter

a Dependent Variable: Start Date          

b All requested variables entered.          

Model Summary              

Model   R   R Square   Adjusted R Square   Std. Error of the Estimate

1   .140a   .020   -.060   6 21:23:59.485

a Predictors: (Constant), Current job category, Tell us about yourself, Age group              

ANOVAa                      

Model       Sum of Squares   df   Mean Square   F   Sig.

1   Regression   261847753029.389   3   87282584343.130   .246   .864b

   Residual   13118282652919.643   37   354548179808.639      

   Total   13380130405949.031   40          

a Dependent Variable: Start Date                      

b Predictors: (Constant), Current job category, Tell us about yourself, Age group                      

Coefficientsa                              

Model       Unstandardized Coefficients       Standardized Coefficients   t   Sig.   95.0% Confidence Interval for B  

       B   Std. Error   Beta           Lower Bound   Upper Bound

1   (Constant)   13700780792.137   668185.308       20504.463   .000   13699426920.101   13702134664.172

   Tell us about yourself   -183963.357   285744.179   -.105   -.644   .524   -762936.058   395009.344

   Age group   35516.564   79490.523   .073   .447   .658   -125546.535   196579.663

   Current job category   43831.359   188870.713   .038   .232   .818   -338857.055   426519.774

a Dependent Variable: Start Date                              

Is this a good model? Why? In other words, what values make you make that determination?

Explanation / Answer

No, this is not a good model.

We can decide this on the basis of p - value (Sig. column in ANOVA table)

In the given problem,

p - value = 0.864

Since this p - value is very large, we do not reject the null hypothesis and hence, the model is not useful in predicting Start Date.