In an experiment to compare the tensile strengths of I = 5 different types of co

Question

In an experiment to compare the tensile strengths of I = 5 different types of copper wire, J = 4 samples of each type were used. The between-samples and within-samples estimates of 2 were computed as MSTr = 2578.9 and MSE = 1394, respectively. Use the F test at level .05 to test Ho :1 2 3 4 5 versusHa : at least two i'sare unequal by completing the ANOVA table below.

In an experiment to compare the tensile strengths of I 5 different types of copper wire, J J 4 samples of each type were used. The between-samples and within-samples estimates of o2 were computed as MST 2578.9 and MSE 1394, respectively. Use the F test at level .05 to at least two His are unequal by completing the 4 versus H ANOVA table below. Source df SS MS f Treatments Error Total

Explanation / Answer

Df for treatment = 5-1=4

Total df =5×4 -1 =20-1=19

Df for error = total - treatment =19-4=15

Ss for treatment =Mstr × df for treatment =2578.9×4 =10315.6

Ss for error = mse × df for error = 1394×15= 20910

Now f = mstr/ mse = 2578.9/ 1394 = 1.85

Now, df1= 4 and df2=15

P value = 0.1718

Since, pvalue >0.05

We fail to reject the null hypothesis.

We accept the null hypothesis.

Source df ss ms f Treatment 4 10315.6 2578.9 1.85 Error 15 20910 1394 Total 19 31225.6

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