Rolled 120 times dice 3,3,2,1,2,1,3,6,1,1,2,4,2,4,3,4,5,6,3,6,3,6,6,5,3,1,4,5,6,
ID: 3250506 • Letter: R
Question
Rolled 120 times dice
3,3,2,1,2,1,3,6,1,1,2,4,2,4,3,4,5,6,3,6,3,6,6,5,3,1,4,5,6,3,2,1,4,6,4,4,3,2,2,1,6,5,4,3,2,6,6,2,1,5,2,1,5,5,1,3,2,6,4,3,3,5,6,3,2,3,3,5,6,3,2,3,2,6,1,3,3,4,2,1,6,2,2,6,1,6,2,6,2,2,5,6,3,3,2,2,2,4,3,3,4,6,6,4,5,4,2,4,1,5,2,6,3,4,6,4,1,3,4,4
Please show steps!
2. After obtaining the data in the number 1, now we want to graph the data into charts and tables to make it easily readable not only for you but for those you are showing as well). Since each outcome of rolling a die is a quantitative variable (unit will be dots), then we would like to place the data into a frequency table including relative frequency, cumulative relative frequency and draw a histogram of this data. (Round your values to three decimal places) 3. Considering the data in the number 1, find the mean, variance, standard deviation of the data, and the z-scores of each of the die outcomes (1, 2, 6) based on the mean and standard deviation. (Round your values to three decimal places) 4. Use the data in the number 1, find the followings a. PO1), PO2), PO3), P(4), P(5), (6) b. POEven), POOdd), POmultiples of 3), POPrime number) c. P (Even n multiples of 3), POOdd u Prime number) d. P Odd Prime number e. Are the events 'Even' and 'Prime number independent? Why?Explanation / Answer
(4)
From the given data we have
P(1) = 15/120 = 0.125
(B)
Number of even outcomes = 25 + 19 + 23 = 67
P(Even) = 67/120 = 0.5583
Number of Odd outcomes = 120 - 67 = 53, P(Odd) = 53/120 = 0.4417
Number of outcomes of multiples of 3 = 49, P(M3) = 49/120 = 0.4083
Number of prime numbers as outcome = 12 + 26 + 25 = 63, P(prime) = 63/120 = 0.525
(C)
Even and multiples of 3 i.e. number 6, number of such outcomes are 23, Required probability = 23/120 = 0.1917
number of odd outcomes = 53, number of prime outcomes = 63, number of odd and prime = 38
Required probability (odd or prime) = (53+63-38)/120 = 0.65
(D)
P(Odd|Prime) = P(Odd and Prime) / P(Prime) = (38/120)/(63/120) = 0.6032
(E)
Yes, events Even and Prime are independent because the occurrance of one event does not affect the occurance other.
Number of 1's 15 Number of 2's 25 Number of 3's 26 Number of 4's 19 Number of 5's 12 Number of 6's 23Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.