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TABLE 6-4 John has two jobs. For daytime at a lry store paid S200 per month, sta

ID: 3251521 • Letter: T

Question

TABLE 6-4 John has two jobs. For daytime at a lry store paid S200 per month, standard commission. His monthly commission is normally distributed with mean deviation S40. At night he works as a waiter, for which his monthly income is normally two distributed with mean $100 and standard deviation S30. John's income levels from these sources are independent of each other. 1. Referring to Table 6-4, for a given month, what is the probability that John's commission. from the jewelry store is less than $640?

Explanation / Answer

1) P(X1 < 640) = P(Z < (640-600)/40) = P(Z < 1) = 0.1587

2) P(70 < X2 < 160) = P((70-100)/30 < Z < (160-100)/30) = P(-1 < Z < 2) = P(Z < 2) - P(Z < -1) = 0.97725 - 0.158655 = 0.818595

3) P(X2 < x) = 0.9, Z = 1.282 = (x - 100)/30, x = 138.46