PLEASE HELP ME ANSWER ALL OF THESE QUESTIONS. The following data come student he

Question

PLEASE HELP ME ANSWER ALL OF THESE QUESTIONS.

The following data come student health records gathered in a survey of women's college athletics. The following data represent the serum cholesterol levels of nine athletes from Lehman College: 110 170 160 200 210 190 130 180 160 Calculate the average cholesterol level Calculate the standard deviation. Assume that this is a sample. Cholesterol is assumed to be normally distributed. Without knowing anything else about the population of female college athletes, what would you infer the mean cholesterol of all female college athletes, what would you infer the mean cholesterol of all female college athletes to be? How much error would you expect, on average, from a sample of 9 people (what is the SE? Sketch the sampling distribution using the answers provided. Make sure to include the mean and 2 standard errors from the mean. Assume that the population mean cholesterol level in all female college athletes is 190 mg/dl. What is the probability of gathering a sample of 9 female college athletes with a mean less than the mean you got from 1A? If a researcher wanted to test the hypothesis that female Lehman College athletes have cholesterol lower than the national average, would the researcher have enough evidence to support that claim?

Explanation / Answer

Let the given variable is X,

X

110

170

160

200

210

190

130

180

160

Total =

1510

Question a)

Sample mean (x bar) = S x / n

                                       = 1510 / 9

                                       = 167.7778

The value of the sample mean is 167.7778

Question b)

Standard deviation = sqrt (S(x – x bar)^2/(n-1))

X

( x - x bar)

( x - x bar)^2

110

-57.7778

3338.2742

170

2.2222

4.9382

160

-7.7778

60.4942

200

32.2222

1038.2702

210

42.2222

1782.7142

190

22.2222

493.8262

130

-37.7778

1427.1622

180

12.2222

149.3822

160

-7.7778

60.4942

Total =

1510

Total =

8355.5558

Standard deviation = sqrt (8355.5558/(9-1))

                                   = 32.3179

The value of the standard deviation is 32.3179

X

110

170

160

200

210

190

130

180

160

Total =

1510

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