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Consider a bowl containing ten balls. Five of the balls are red. Three of the ba

ID: 3253625 • Letter: C

Question

Consider a bowl containing ten balls. Five of the balls are red. Three of the balls are green. Two of the balls are white.

4. If one ball is randomly selected from the bowl, what is the probability that a green ball is selected?

5. If one ball is randomly selected from the bowl, what is the probability that the ball selected is not green?

6. If one ball is randomly selected from the bowl, what is the probability that the ball selected is red or green?

7. If one ball is randomly selected from the bowl, what is the probability that the ball selected is neither red nor green?

8. If one ball is randomly selected from the bowl, what is the probability that the ball selected is red and green?

Explanation / Answer

Red Balls = 5

Green Balls = 3

White Balls = 2

So,

Total balls = 5 + 3 + 2 = 10

4. P(Green) = 3/10 = 0.3

5. P(Not Green) = 1 - P(Green) = 1 - 0.3 = 0.7

6. P(Red or green) = 5/10 + 3/10 = 8/10 = 0.8

7. P(Neither red nor green) = 1 - P(Red or green) = 1 - 0.8 = 0.2

8. P(Red and green) = 0 [Since a ball having both the color is not possible].

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