A box contains 15 resistors, 6 diodes, and 9 capacitors. 2 parts are taken from

Question

A box contains 15 resistors, 6 diodes, and 9 capacitors. 2 parts are taken from the box. Consider the following events: A) the first part is resistor B) the first part is diode C) the first part is capacitor D) the second part is resistor E) the second part is diode F) the second part is capacitor Find the following probabilities a) p(A) = ? b) p(B) = ? c) p(C) = ? d) p(D/A) = ? e) p(D/B) = ? f) p(D/C) = ? g) p(E/A) = ? h) p(E/B) = ? i) p(E/C) = ? j) p(F/A) = ? k) p(F/B) = ? l) p(F/C) = ? Find probabilities to take a) 2 resistors b) 2 diodes c) one diode and one capacitor We have taken 2 parts form the box. What are probabilities that we have taken a) at least one resistor b) at least one diode c) at least one capacitor There are 20 students in the group. 9 students have excellent preparation for the exam, 6 have good level of knowledge, 3 have average level of knowledge, and 2 are bad prepared. Probability that student pass the exam for excellently prepared student is 100%, if student have good level of knowledge - 90%, for average level of know ledge it is 60%, and for bad prepared student it is 20%. a) Find probability that student from this group pass the exam. Student has passed the exam. Find probabilities that this student has b) excellent preparation c) good level of knowledge d) average level of knowledge e) bad preparation

Explanation / Answer

1 a ns) p(A) = NUMBER OF RESTIORS / TOTAL NUMBER OF ELEMENTS =15 /30=1/2

B ANS) P(B) = NUMBER OF DIODES / TOTAL NUMBER OF ELEMENTS =6/30 = 1/5

C ANS) P (C) = NUMBER OF CAPACITORS /TOTAL NUMBER OF ELEMNTS =9/30= 3/10

DANS) = P(D/A) = P(D) P(A) AS THIS IS INDEPENDENT = 1/2*1/2= 1/4

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