To test H_0:mu = 100 versus H_1:mu notequalto 100, a simple random sample size o

Question

To test H_0:mu = 100 versus H_1:mu notequalto 100, a simple random sample size of n = 22 is obtained from a population that is known to be normally distributed. Answer parts (a)-(d). (a) If x bar = 105.7 and s = 8.2, compute the test statistic. t = 3.260 (Round to three decimal places as needed.) (b) If the researcher decides to test this hypothesis at the alpha = 0.01 level of significance, determine the critical values. The critical values are (Use a comma to separate answers as needed. Round to three decimal places as needed.)

Explanation / Answer

a) here std error of mean =std deviation/(n)1/2 =1.7482

hence test stat t=(X-mean)/std errror =(105.7-100)/1.7482=3.260

b) critical value for 2 tailed test at 21 degree of freedom and 0.01 level of significance =2.831

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