In a test of weight loss programs, 200 subjects were divided such that 40 subjec
ID: 3256659 • Letter: I
Question
In a test of weight loss programs, 200 subjects were divided such that 40 subjects followed each of 5
diets. Each was weighed a year after starting the diet and the results are in the ANOVA table below. Use a 0.05
significance level to test the claim that the mean weight loss is the same for the different diets.
Source of Variation
SS
df
MS
F
P-value
F crit
Between Groups
367.850367.850
44
91.9624891.96248
2.76842.7684
0.0285980.028598
2.4179632.417963
Within Groups
6477.6356477.635
195195
33.2186433.21864
Total
6845.4856845.485
199199
Should the null hypothesis that all the diets have the same mean weight loss be rejected?
A. No, because the P-value is less thanless than the significance level.
B. Yes,because the P-value is less thanless than the significance level.
C. Yes, because the P-value is greater thangreater than the significance level.
D.No, because the P-value is greater thangreater than the significance level
Source of Variation
SS
df
MS
F
P-value
F crit
Between Groups
367.850367.850
44
91.9624891.96248
2.76842.7684
0.0285980.028598
2.4179632.417963
Within Groups
6477.6356477.635
195195
33.2186433.21864
Total
6845.4856845.485
199199
Explanation / Answer
We have,
Alpha = 0.05
From given table,
p-value = 0.028599
We observe that,
p-value < alpha
so Reject the null hypothesis ( By decision rule)
Therefore,
Answer :(B). Yes,because the P-value is less than the significance level.
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