In an expiriment of 15 telephone callers to a company were put on hold with an a
ID: 3257092 • Letter: I
Question
In an expiriment of 15 telephone callers to a company were put on hold with an advertisment, comedy Musak, or classical music in the background. Data was then collected on the telephone holding times for each combination of type and repeat time. Also, the message randomly assigned to each caller would repeat after five, seven and a half, or ten minutes.
a. State the null hypothesis to which the F test statistic in the message row refers.
Choose the correct null hypothesis below.
A. THe length and type of message have an effect on customer hold time
B.The legnth of the message has no effect on customer hold time.
C. The legnth and type of message have no effect on customer hold time.
D. The type of message had no effeect on customer hold time.
b. Show how to use the mean squares to construct the F test statistic for the messagemain effect, report is P-Value, and interpret.
A. F= mean square for message/mean square for error
B. F= mean square for repeat/ mean square for message
C. F= mean square for message/mean square for repeat
D. F= mean square for repeat/ mean square for error
P-Value=
Interpret the P-Value for the message main effect. Use a 0.05 leevel of significance
A. Since p>0.05, there is no evidence of an effect due to the type of message
B. Since p>0.05, there is evidence of an effect due to the type of message
C. Since p<0.05, there is evidence of an effect due to the type of message
D. Since p<0.05, there is no evidence of an effect due to the type of message
c. On what assumptions is the analysis based on
A. Independent random samples of at least 10 equal standard deviations
B. Normal population distributions, equal standard deviations and random samples
C. Independent random samples of at least 10 equal sample sizes
D. Normal population distributions, equal standard deviations, equal samples sizes
source DF SS MS F P Message 3 88.41 27.16 2.30 0.146 Repeat 2 280.14 140.07 11.86 0.003 Error 9 106.29 11.81 Total 14 467.91Explanation / Answer
Question a)
Answer:
Question b)
Answer:
P-value = 0.146
Question c)
Answer:
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.