1.Which of the following are true statements about hypothesis tests to compare t
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Question
1.Which of the following are true statements about hypothesis tests to compare two population means? A. The z-distribution is used to obtain the critical value for the rejection region and decision rule whenever at least one of the sample sizes is sufficiently large (either n 1 1 or n 2 2 is at least 30). B. D 0 0 is the amount by which the population means are hypothesized to differ. Although this amount if often 0 (if the means are hypothesized to be equal), it does not have to be zero. C. Both A and B. D. Neither A or B.
2.Selling prices for 230 diamonds evaluted by two different diamond ratings agencies (GIA and HRD) were collected and the data was analyzed using the Microsoft Excel Data Anlaysis Toolpak. The following results were generated in Excel inputting alpha .05 in the Excel dialog box.
Based on these Microsoft Excel Data Analysis results, if the the hypothesis test is testing "whether the mean retail sales price of GIA is less than the mean retail sales price of HRD," the conclusion of this hypothesis test based on a .05 level of significance: is:
A.Since the decision rule is if z-test statistic > 1.96, the test statistic -4.46 indicates the null hypothesis should not be rejected at the .05 level of significance, indicating there is not sufficient evidence to suggest the mean retail selling price of GIA is less than the mean retail selling price of HRD.
B.Since the decision rule is if z-test statistic < -1.96, the test statistic -4.46 indicates the null hypothesis should be rejected at the .05 level of significance, indicating there is sufficient evidence to suggest the mean retail selling price of GIA is less than the mean retail selling price of HRD.
C.Since the decision rule is if z-test statistic > 1.645, the test statistic -4.46 indicates the null hypothesis should not be rejected at the .05 level of significance, indicating there is not sufficient evidence to suggest the mean retail selling price of GIA is less than the mean retail selling price of HRD.
D.Since the decision rule is if z-test statistic < -1.645, the test statistic -4.46 indicates the null hypothesis should be rejected at the .05 level of significance, indicating there is sufficient evidence to suggest the mean retail selling price of GIA is less than the mean retail selling price of HRD.
Selling prices for 230 diamonds evaluted by two different diamond ratings agencies (GIA and HRD) were collected and the data was analyzed using the Microsoft Excel Data Anlaysis Toolpak. The following results were generated in Excel inputting alpha .05 in the Excel dialog box.
Based on these Microsoft Excel Data Analysis results, if the the hypothesis test is testing "whether the mean retail sales price of GIA is less than the mean retail sales price of HRD,":
A.Since the p-value is larger than the level of significance (.05), the null hypothesis will not be rejected.
B.the p-value of this hypothesis test is 4.1505.
C.the p-value of this hypothesis test is appoximately zero.
D.the p-value of this hypothesis test is 8.3009.
4.The operations manager at a distribution center has two choices of routes for making a weekly delivery to a retail store. He wants to choose the route that will require, on average, the least amount of time for the delivery. To determine which route is faster, on average, he randomly selected 10 days and had the driver take Route 1, and then randomly selected 10 different days and had the driver take Route 2. The amount of time required to make the delivery each day was recorded. From the data, the manager constructed the following 95% confidence interval for the difference in mean delivery times (Route 1 - Route 2): (-1 minutes, 9 minutes). Based on this confidence interval, which of the following is a correct statement?
Choose the correct answer below.
A.There is not enough evidence at the 5% significance level to indicate that the average delivery times for the two routes are the same.
B.There is not enough evidence at the 5% significance level to indicate that one route is faster, on average, since 0 falls within the bounds of the confidence interval.
C.There is evidence at the 5% significance level to indicate that one route is faster, on average, since one bound is close to 0.
D.There is evidence at the 5% significance level to indicate that one route is faster, on average, since 0 falls between the bounds of the confidence interval.
5.When conducting a hypothesis test about the relationship between two population means using small samples the test can be conducted either 1) assuming the samples are drawn from populations that have equal variances or 2) assuming the samples are drawn from populations whose variances are unequal. Which of the following are true statements?
A.If the F-test Two Sample for Variances is used to analyze the data to and the results are used to conduct a hypothesis test to determine whether the population variances are equal or unequal, you will definitely know whether the populations sampled from have equal variances or not.
B.If the F-test Two Sample for Variances is used to analyze the data and the results are used to conduct a hypothesis test to determine whether the population variances are equal or unequal, even if the null hypothesis is rejected it is possible the populations variances are actually equal.
C.If the F-test Two Sample for Variances is used to analyze the data and the results are used to conduct a hypothesis test to determine whether the population variances are equal or unequal, even if the null hypothesis is not rejected it is possible the populations variances are actually unequal.
D.B & C.
6.The PowerPoint presentation showed two examples of Excel output for the Papermills data file:
When Excel is used to analyze the data it will provide you with one of these sets of results depending on which sample data is entered first in the dialog box. How can you determine from these results whether your critical value corresponds to the upper-tail or the lower-tail rejection region?
A.Since both numbers are positive (not negative) they must both be upper tail critical values.
B.Since the second example has a critical value smaller than 1 the critical value F=0.42 must be the lower-tail critical value corresponding to a decision rule of:
if F-test statistic < 0.42 then reject
H0
C.Since the first example has a critical value larger than 1 the critical value F=2.38 must be the upper-tail critical value corresponding to a decision rule of:
if F-test statistic < 2.38 then reject
H0
D.None of the above
7.Tests of product quality using human inspectors can lead to serious inspection error problems. To evaluate the performance of inspectors in a new company, a quality manager sampled 12 novice and 12 expert inspectors to determine whether there is a difference in the variability of detecting defective products.
A.The hypothesis test described is a one-tailed hypothesis test.
B.The hypothesis test described is a two-tailed hypothesis test.
8.
A company tests its new novice product inspectors by comparing the variability in the number of defective items spotted by its novice inspectors to the variability in the number of defective items spotted by its expert product inspectors. The company wants to determine whether there is a difference in the variability of the number of defective items spotted by its novice and expert product inspectors. Given the Exel results provided above, if the company uses the .10 level of significance, the correct conclusion of this hypothesis test is:
A.Since the two-tail p-value is .0955, the correct conclusion is to reject the null hypothesis test at the .10 level of significance, there is sufficient evidence to suggest there is a difference in the variability of the novice and expert product inspectors.
B.Since the one-tail p-value is .0955, the correct conclusion is to reject the null hypothesis test at the .10 level of significance, there is sufficient evidence to suggest there is a difference in the variability of the novice and expert product inspectors.
C.Since the one-tail p-value is .0955, the two-tail p-value is .1910, so the correct conclusion is to fail to reject the null hypothesis test at the .10 level of significance, there is not sufficient evidence to suggest there is a difference in the variability of the novice and expert product inspectors.
D.None of the above.
9.In a Single Factor ANOVA with five treatments, what are the correct null and alternative hypotheses?
A.Upper H 0H0: mu 1 equals mu 2 equals mu 3 equals mu 4 equals mu 51=2=3=4=5
Upper H Subscript aHa: all of the treatment means differ
B.Upper H 0H0: mu 1 equals mu 2 equals ... equals mu Subscript k1=2=...=k
Upper H Subscript aHa: mu 1 not equals mu 2 not equals ... not equals mu Subscript k12...k
C.Upper H 0H0: mu 1 equals mu 2 equals mu 3 equals mu 4 equals mu 51=2=3=4=5
Upper H Subscript aHa: mu 1 not equals mu 2 not equals mu 3 not equals mu 4 not equals mu 512345
D.Upper H 0H0: mu 1 equals mu 2 equals mu 3 equals mu 4 equals mu 51=2=3=4=5
Upper H Subscript aHa: at least two of the five treatment means differ
9. MST measures
A.the variability between the treatment means
B.the variability within the treatments
C.the sample variances
D.none of the above
10.Used car buyers might expect the price they pay to be related to the quality rating for the condition of the car (Average, Good, Excellent) as evaluated by the car dealer. Listed below are the Excel Data Analysis results for 160 purchases:
In this scenario:
A.the factor is the quality rating, the three treatments are Average, Excellent, and Good, the experimental units are the 160 cars, and the dependent variable is the price paid for the car.
B.the three factors are Average, Excellent, and Good, the experimental units are the 160 cars, and the dependent variable is the price paid for the car.
C.the treatments are the 160 cars, the factor is the quality rating, and the dependent variable is the
D.None of the above.
11. Used car buyers might expect the price they pay to be related to the quality rating for the condition of the car (Average, Good, Excellent) as evaluated by the car dealer. Listed below are the Excel Data Analysis results for 160 purchases, entering alpha=.05 into the MS Excel dialog box:
For this hypothesis test, the correct conclusion is:
A.Reject Upper H 0H0, at the .05 level of significance, there is sufficient evidence to suggest the mean price of at least one of the quality ratings differs.
B.Accept Upper H 0H0, at the .05 level of significance, there is sufficient evidence to prove the mean price of all of the quality ratings are the same.
C.Fail to reject Upper H 0H0, at the .05 level of significance, there is not sufficient evidence to suggest the mean price of at least one of the quality ratings differs.
D.None of the above.
12.The rejection region for the Single Factor Anova
A.is located in the lower tail of the F distribution, since only relatively small F values support the alternative hypothesis (that the treatments have an effect on the population
means)
B.can be located in either the upper-tail of the F-distribution or the lower-tail of the F-distribution
C.is located in the upper tail of the F distribution, since only large F values support the alternative hypothesis (that the treatments have an effect on the population
means)
D.is located in the upper tail of the z distribution, since only large z values support the alternative hypothesis (that the treatments have an effect on the population means)
13.A certain HMO is attempting to show the benefits of managed care to an insurance company. The HMO believes that certain types of doctors are more cost-effective than others. One theory is that certification level is an important factor in measuring the cost-effectiveness of physicians. To investigate this, the HMO obtained independent random samples of 19 physicians from each of the three certification levels ( Board certified (C); Uncertified, board eligible (E); and Uncertified, board ineligible (I)) and recorded the total per-member, per-month charges for each (a total of 57 physicians). Identify the treatments for this experiment.
A.the three certification groups: C, E, and I
B.the total per-member, per-month charge
C.the 57 physicians
D.the HMO
14. In a Single Factor ANOVA, which of the following is true?
A.if the null hypothesis is rejected, it may still be possible that two or more of the population means are equal
B.if the computed F statistic exceeds the critical F value we will not reject H0 since there is sufficient evidence the treatment has an effect on the mean of the dependent variable
C.if the computed F statistic exceeds the critical F value we may reject H0 since there is sufficient evidence the treatment has no effect on the mean of the dependent variable
D.all of the above
15. In the article “Deep vs. Surface Learning: An Empirical Test of Generational Differences,” the authors hypothesize “H6: Gen Xers have a stronger Surface Approach to Learning than do Boomers.”
Which of the following represents this hypothesis?
A.H0:µSubscript XSAXSA µSubscript BSABSA = 0H6:µSubscript XSAXSA µSubscript BSABS< 0
B.H0:µSubscript XSAXSA µSubscript BSABSA = 0H6:µSubscript XSAXSA µSubscript BSABSA 0
C.H0:µSubscript XSAXSA -µSubscript BSABSA = 0H6:µSubscript XSAXSA µSubscript BSABSA > 0
D.None of the above.
16.Which of the following statements is correct?
AMillennials had the highest mean surface approach to learning score since µSubscript MSAMSA=43.25
B.Millennials had the highest mean surface approach to learning score since x overbar Subscript MSAxMSA=43.25
C.Millennials had the highest mean surface approach to learning score since µSubscript MSAMSA=49.52
D.Millennials had the highest mean surface approach to learning score since x overbar Subscript MSAxMSA=49.52
17.Which of the following statements is correct?
A.The confidence interval estimate for hypothesis 1 can be interpreted as: we are 95% confident the interval (5.79, 9.79) includes the true difference between the mean deep approach to learning score and the mean surface approach to learning score of Baby Boomers.
B.The confidence interval estimate for hypothesis 1 can be interpreted as: we are 95% confident the interval (5.79, 9.79) includes the true mean deep approach to learning score of Baby Boomers.
C.The confidence interval estimate for hypothesis 1 can be interpreted as: we are 95% confident the interval (5.79, 9.79) includes the true difference between the mean deep approach to learning score of Baby Boomers and the mean deep approach to learning score of Millennials.
D.None of the above.
18
Based on the results in Table 2, which hypothesis test has the largest test statistic?
Test Post-hoc Comparisons
Dependent Variable
(I) Generation Groups
(J) Generation Groups
Mean Difference (I-J) Std. Error Sig.
95% Confidence Interval
Lower Bound Upper Bound
Deep Approach to Learning
H1: Baby Boomers Millennials 7.790* .815 .000 5.79 9.79 H2: Baby Boomers Generation X 5.722* .891 .000 3.54 7.91 H3: Generation X Millennials 2.067* .509 .000 .82 3.31
Surface Apathetic Approach to Learning
H4: Millennials Baby Boomers 6.270* .803 .000 4.30 8.24 H5: Millennials Generation X 2.429* .501 .000 1.20 3.66 H6: Generation X Baby Boomers 3.840* .877 .000 1.69 5.99
A.
H1
B.
H2
C.
H3
D.
H4
E.
H5
F.
H6
19
Once the authors found “significant” differences using the one-way ANOVA, why were additional data analysis methods used to analyze each of the six hypotheses? Which of the following statements answer this question?
A.
The ANOVA hypothesis test for the deep approach to learning tests the hypothesis that H0:
µSubscript BDLBDL
=
µSubscript XDLXDL
=
µSubscript MDLMDL
against the alternative hypothesis that there is evidence that at least one population’s mean differs. In order to determine whether there is evidence to support each of the individual hypothesized relationships, a test for the difference between each of the two means must be conducted.
B.
The ANOVA hypothesis test is always a two-tailed test but the test for the difference between the two means can be a one-tailed test, which is what each hypothesis specifies.
C.
Both A and B.
D.
Neither A or B.
Explanation / Answer
1 answer is
B. D 0 0 is the amount by which the population means are hypothesized to differ. Although this amount if often 0 (if the means are hypothesized to be equal), it does not have to be zero
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