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please do NOT use excell...3 answers ... hw 6.3#8 a. Assume that human body temp

ID: 3257391 • Letter: P

Question

please do NOT use excell...3 answers ... hw 6.3#8

a. Assume that human body temperatures are normally distributed with a mean of 98.22°Fand a standard deviation of 0.64 degrees 0.64°F. A hospital uses 100.6°F as the lowest temperature considered to be a fever. What percentage of normal and healthy persons would be considered to have a fever? Does this percentage suggest that a cutoff of 100.6 degrees is appropriate?

b. Physicians want to select a minimum temperature for requiring further medical tests. What should that temperature be, if we want only 5.0% of healthy people to exceed it? (Such a result is a false positive, meaning that the test result is positive, but the subject is not really sick.)

1)The percentage of normal and healthy persons considered to have a fever is _____ % (Round to 2 decimal places as needed.)

2)Does this percentage suggest that a cutoff of 100.6°F is appropriate?
A.No, because there is a small probability that a normal and healthy person would be considered to have a fever.
B.No, because there is a large probability that a normal and healthy person would be considered to have a fever.
C.Yes, because there is a large probability that a normal and healthy person would be considered to have a fever.
D.Yes, because there is a small probability that a normal and healthy person would be considered to have a fever.

3. The minimum temperature for requiring further medical tests should be________degrees F° if we want only 5.0% of healthy people to exceed it. (Round to 2 decimal places as needed)

Explanation / Answer

a)

We first get the z score for the critical value. As z = (x - u) / s, then as          
          
x = critical value =    100.6      
u = mean =    98.22
          
s = standard deviation =    0.64      
          
Thus,          
          
z = (x - u) / s =    3.71875
          
Thus, using a table/technology, the right tailed area of this is          
          
P(z >   3.765625   ) = 0.0001    [ANSWER]

OPTION C:

C.Yes, because there is a small probability that a normal and healthy person would be considered to have a fever. [ANSWER]

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b)

First, we get the z score from the given left tailed area. As          
          
Left tailed area =    0.95      
          
Then, using table or technology,          
          
z =    1.644853627      
          
As x = u + z * s,          
          
where          
          
u = mean =    98.22   
z = the critical z score =    1.644853627      
s = standard deviation =    0.64      
          
Then          
          
x = critical value =    99.27270632