1a.) One sample has n = 17 with SS = 1646, and a second sample has n = 17 with S

Question

1a.) One sample has n = 17 with SS = 1646, and a second sample has n = 17 with SS = 1710. (a) Find the pooled variance for the two samples. (Use/round to 2 decimal places.) Pooled variance = ______________

1b.) Compute the estimated standard error for the sample mean difference. (Use/round to 3 decimal places.) Estimated standard error = ___________

1c.) If the sample mean difference is 6 points, is this enough to reject the null hypothesis and conclude that there is a significant difference for a two-tailed test at the 0.10 level? (Use/round to 3 decimal places.)

t-critical = ± __________ t = __________

1d.) What is the decision regarding the null? Accept the null or reject it? Write "accept" or "reject" in the blank. __________

1e.) Calculate the percentage of variance accounted for (r2) to measure the effect size for an 6-point mean difference (Use/round to 3 decimal places). r2 = _____________

1f.) What size is the effect? Write "small", "medium", or "large" in the blank. __________

Explanation / Answer

a) pooled variance = (SS1 + SS2)/(n1+n2-2) =(1646+1710)/32=104.875

b) Estimated standard error = sp *sqrt(1/n1 + 1/n2)

= sqrt(104.875*(2/17))=3.51258242524

c) TS = (difference in sample mean)/Estimated standard error = 6 /3.51258242524 =1.70814496961

df = n1+n2 -2 = 32

for  a two-tailed test at the 0.10 level

t-critical = 1.694   

t= 1.70814496961

d) since t > t-critical

we reject the null

According to chegg policy ,we have to answer 1 question or minimum 4 sub-parts

which i solved , so ask remaing question again

Related Questions

Navigate

• Browse (All)
• Browse 1
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.