Need help to understand part c of the below question: The Association for Resear

Question

Need help to understand part c of the below question:

The Association for Research and Enlightenment (ARE) in Virginia Beach, VA, offers daily demonstrations of a standard technique for testing extrasensory perception (ESP). A “sender” is seated before a box on which one of five symbols (plus, square, star, circle, wave) can be illuminated. A random mechanism selects symbols in such a way that each symbol is equally likely to be illuminated. When a symbol is illuminated, the sender concentrates on it and a “receiver” attempts to identify which symbol has been selected. The receiver indicates a symbol on the receiver’s box, which sends a signal to the sender’s box that cues it to select and illuminate another symbol. This process of illuminating, sending, and receiving a symbol is repeated 25 times. Each selection of a symbol to be illuminated is independent of the others. The receiver’s score (for a set of 25 trials) is the number of symbols that s/he correctly identifies. For the purpose of this exercise, please suppose that ESP does not exist.

(a) How many symbols should we expect the receiver to identify correctly?

(b) The ARE considers a score of more than 7 matches to be indicative of ESP. What is the probability that the receiver will provide such an indication?

c)The ARE provides all audience members with scoring sheets and invites them to act as receivers. Suppose that, as on August 31 2002, there are 21 people in attendance: 1 volunteer sender, 1 volunteer receiver, and 19 additional receivers in the audience. What is the probability that at least one of the 20 receivers will attain a score indicative of ESP?

Explanation / Answer

c)given thatThe number Y out of 20 receivers who show an "indication" according to given (a) is distributed YBinom(20,0.1091228).YBinom(20,0.1091228).from binomial distribution we have Thus P(Y1)=1P(Y=0)0.90.P(Y1)=1P(Y=0)0.90.

so we have 90% of such audience

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