On a national mathematics assessment test, a random sample of 120 twelfth grade
ID: 3259795 • Letter: O
Question
Explanation / Answer
Solution:-
a) State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.
Null hypothesis: > 145
Alternative hypothesis: < 145
Note that these hypotheses constitute a one-tailed test. The null hypothesis will be rejected if the sample mean is too small.
Formulate an analysis plan. For this analysis, the significance level is 0.05. The test method is a one-sample t-test.
Analyze sample data. Using sample data, we compute the standard error (SE), degrees of freedom (DF), and the t statistic test statistic (t).
SE = s / sqrt(n)
S.E = 3.104
DF = n - 1 = 120 - 1
D.F = 119
t = (x - ) / SE
c) t = 1.61
tcritical = 1.658
Critical region is t greater than 1.658.
where s is the standard deviation of the sample, x is the sample mean, is the hypothesized population mean, and n is the sample size.
The observed sample mean produced a t statistic test statistic of 1.61. We use the t Distribution Calculator to find P(t > 1.61) = 0.055
Thus the P-value in this analysis is 0.055
Interpret results. Since the P-value (0.055) is greater than the significance level (0.01), we cannot reject the null hypothesis.
d) From the above test we have sufficient evidence in the favor of the claim that mean score for all twelfth grade students who took the test is atleast 145.
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