number of green peas with green pods 0 1 2 3 4 5 6 7 8 P(X) 0+ 0+ 0.007 0.026 0.
ID: 3260108 • Letter: N
Question
number of green peas with green pods
0 1 2 3 4 5 6 7 8
P(X) 0+ 0+ 0.007 0.026 0.071 0.29 0.268 0.277 0.102
The accompanying table describes results from eight offspring peas. The random variable x represents the number of offspring peas with green pods. Complete parts (a) through (d). a. Find the probability of getting exactly 7 peas with green pods. (Type an integer or a decimal.) b. Find the probability of getting 7 or more peas with green pods. (Type an integer or a decimal.) c. Which probability is relevant for determining whether 7 is an unusually high number of peas with green pods, the result from part (a) or part (b)? The result from part (b) The result from part (a) d. Is 7 an unusually high number of peas with green pods? Why or why not? Use 0.05 as the threshold for an unusual event. A. No, since the appropriate probability is less than 0.05, it is not an unusually high number. B. No, since the appropriate probability is greater than 0.05, it is not an unusual high number. C. Yes, since the appropriate probability is less than 0.05, it is an unusually high number. D. Yes, since the appropriate probability is greater than 0.05, it is an unusually high number.Explanation / Answer
A) .A probability distribution is a description that gives the probability for each value of the random variable.
The table, given in the problem statement, gives a probability distribution of the random variable x, the number of peas with green pods. The probability of getting exactly 7 peas with green pods is 0.277
B). To find the probability of getting 7 or more peas with green pods, add the probabilities for each value of x that is greater than or equal to 7.
The probability of getting exactly 7 peas with green pods was found in part (a) to be .
The only value of x that is greater than 7 in the given table is 8.
Find the probability of getting exactly 8 peas with green pods. 0.277 P(8) = 0.102
Now add the two probabilities, P(7) and P(8) ,
to find the probability of getting 7 or more peas with green pods. = 0.277 = 0.102
P(7 or more) = P(7 or 8) = 0.277 + 0.102 = 0.379
C). In general, x successes among n trials is an unusually high number of successes if the probability of x or more successes is unlikely with a probability of 0.05 or less.
The probability that is relevant for determining whether 7 is an unusually high number of peas with green pods is P(7 or more).
Since the probability P(7 or more) was found in part (b), the probability from part (b) is relevant in determining whether 7 is an unusually high number of peas with green pods.
D).Use 0.05 as the threshold for an unusual event. Recall that the probability of 7 or more peas with green pods is .
Since P(7 or more) is greater than 0.05, it is not an unusually high number.
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