\"The genome of virus MY30 is a circular double-stranded DNAmolecule 3 kb (kilob

Question

"The genome of virus MY30 is a circular double-stranded DNAmolecule 3 kb (kilobases) long.If the number of thymine in the MY30genome is 2000, what is the % of cytosine in the genome? Showwork."

There was a hint given out with this question which is asfollows:   "The original DNA molecule contains 3 kb X 2 =6,000 bases."


Here's how I did it:

The % of Thymine is: (2,000/6,000) X 100%= 33.3% (This is also the % of Adenine in the genomesince Chargaff's rule states that %Adenine = %Thymine)

The total content of both Thymine and Adenine is therefore66.6%. The remaining 33.4% then belong to the total content of Guanine andCytosine. Therefore, the cytosine content is half of 33.4% (Chargaff's rule states that %Guanine = %Cytosine) which is16.7%.

Explanation / Answer

      Yes, your answer is absolutelyright. Out of 6000 bases when 2000 bases are thyminethere will be 2000 bases of       Adenine which is inaccordance to Chagaff's rule.       Both adenine and guaninetogether constitutes to 66.6% and individuallythey constitute 33.3% of the total DNA.       The rest of the 2000 baseswill be cytosine and guanine which means there will be 1000cytosines and 1000 guanines       and these togetherconstitute to 33.4% and individually they constitute16.67%.       Hence the percentage ofcytosine content in the genome is 16.7.        

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