In a random sample of five microwave ovens, the mean repair cost was exist70.00

Question

In a random sample of five microwave ovens, the mean repair cost was exist70.00 and the standard deviation was exist14.00. Assume the population is normally distributed and use a 1-distribution to construct a 99% confidence interval for the population mean mu. What is the margin of error of mu? Interpret the results The 99% confidence interval for the population mean mu is (___ - ____). (Round to two decimal places as needed.) The margin of error is ______. (Round to two decimal places as needed.) Interpret the results. Choose the correct answer below. A. With 99% confidence, it can be said that the repair cost between the bounds of the confidence interval. B. If a large of microwaves are taken approximately 99% of them will have repair costs between the bounds of the confidence interval. C. With 99% confidence, it can be said that the population mean repair cost is between the bounds of the confidence interval. D. It can be said that 99% of microwaves have a repair cost between the bounds of the confidence interval.

Explanation / Answer

The statistical software output for this problem is:

One sample T confidence interval:
: Mean of population

99% confidence interval results:

Hence,

99% confidence interval is:

(41.17, 98.83)

Margin of error = (98.83 - 41.17)/2 = 28.83

Interpretation: Option C is correct.

Mean Sample Mean Std. Err. DF L. Limit U. Limit 70 6.2609903 4 41.173795 98.826205

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