In one town, 71% of adults have health insurance. Find the probability that 4 ad

Question

In one town, 71% of adults have health insurance. Find the probability that 4 adults selected at random from the town at have health insurance Round to the nearest thousandth if necessary. A. 0 056 B. 0 254 C. 0 710 D. 2 840 You are dealt two cards successively (without replacement) from a shuffled deck of 52 playing cards Find the probability that both cards are black. Express your answer as a simplified fraction. A. 1/2.652 B. 25/102 C. 25/51 D. 13/51 In a certain country, the true probability of a baby being a boy is 0 535. Among the next nine randomly selected births in the country, what is the probability that at least one of them is a girt? The probability is (Round to three decimal places as needed.)

Explanation / Answer

1) probabilty that all 4 have health insurance=(0.71)4 =0.254 option B

2)probability =(26/52)*(25/51)=25/102 option B

3)probability that at least one is girl =1-P(all nine are boys)=1-(0.535)9 =1-0.004=0.996

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