There are 3 types of Chi- square anslysis: Test of independence, test for homoge
ID: 3261430 • Letter: T
Question
There are 3 types of Chi- square anslysis: Test of independence, test for homogeneity, and There are 3 types of ON-square analysis: Test of independence, test for homogeneity, and·… F in the blank D Question 56 0.5 pts Refer to the correlation matrix below What is the p-value of the correlation between reading score and math score? (Fill in the blank with a number) Correlations reading score Pearson Correlation Sig. (2-tailed) 597 630053 455 200 200 200 597 200 570 200 writing score Pearson Correlatio 256 Sig (2-tailed) 200 662 200 200 617 200 631 200 029 680 200 128 071 200 arson Correlation200 Sig. (2-tailed) math score Pearson Correlation 200 631 200 200 science score Pearson Correlatorn Pearson Correlation200 6301570" Sig. (2-tailed) 200 053 455 200 200 029 680 200 -128 071 200 female Pearson Correlation Sig. (2-tailed) 256 200 200 " Correlation is significant at the 0.01 level (2-tailed)Explanation / Answer
Solution:
(55). There are 3 different types chi square analysis.
1) Test for Homogeneity
2) Test of Independence.
3) Goodness of fit.
There are 3 different types chi square analysis. Test of Independence , test for Homogeneity and Goodness of fit.
(56). P-value = 0.00001 i.e The P-Value is < 0.00001. The result is significant at p < 0.01.
(57). P-value is less than level of significance so,we reject the null hypothesis.i.e Reject Ho.
(58). We have to given that Z = 4.21 Hence, p-value = 0.0000026,Therefore P-value is less than the level of sigificance it means percentage are statistically different.
(d) is the correct answer.
(65).From the T-test we have to calculate ,t-test of comparison i.e
Hence,p-value is greator than the level of significance(0.05) so ,we fail to reject the null hypothesis.It means two means are statistically different from one another.
The , Statement is True.
Cheers!!
Difference 1.179 Standard error 1.013 95% CI -1.0516 to 3.4088 t-statistic 1.163 DF 11 Significance level P = 0.2694Related Questions
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