Thompson Photo Works purchased several new, highly sophisticated processing mach

Question

Thompson Photo Works purchased several new, highly sophisticated processing machines. The production department needed some guidance with respect to qualifications needed by an operator. Is age a factor? Is the length of service as an operator (in years) important? In order to explore further the factors needed to estimate performance on the new processing machines, four variables were listed:

      Thirty employees were selected at random. Data were collected for each, and their performances on the new machines were recorded. A few results are:

As age increases by one year, how much does estimated performance on the new machine increase? (Round your answer to 3 decimal places.)

Carl Knox applied for a job at Photo Works. He has been in the business for 6 years and scored 325 on the mechanical aptitude test. Carl’s prior on-the-job performance rating is 60, and he is 57 years old. Estimate Carl’s performance on the new machine. (Round your answer to 3 decimal places.)

Thompson Photo Works purchased several new, highly sophisticated processing machines. The production department needed some guidance with respect to qualifications needed by an operator. Is age a factor? Is the length of service as an operator (in years) important? In order to explore further the factors needed to estimate performance on the new processing machines, four variables were listed:

Explanation / Answer

a) The given equation is known as Multiple regression equation.

b) There is 1 dependent and 4 independent variables.

DEPENDENT:

Y: Performance on new machine

INDEPENDENT:

X1, X2, X3, X4 are independent variables

c) The value 0.412 is the regression coefficient of the variable X3

d) As the coefficient of the variable X4 i.e. age is 0.009, so when the age increases by 1 year, then Y i.e. performance on neww machine increases by 0.009.

e) Putting X1=6 , X2=325 , X3=60 , X4=57 in the multiple regression equation, we get

Y= 11.2 + 0.7(6) + 0.786(325) + 0.412(60) + 0.009(57)= 296.083

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