An instructor in a large lecture class found at the end of the semester that the

Question

An instructor in a large lecture class found at the end of the semester that the total point distribution in his class was approximately normal with a mean of 530 and a standard deviation of 80 r 10% of the class are to receive as(this instructor grades on a curve), what is the lowest number of 428 632 610 An instructor in a large lecture class found at the end of the semester that the total point distribution in his class was approximately normal with a mean of 530 and a standard deviation of 80. About what percent of students will score between 370 and 690? 95% 68% 99.7% An instructor in a large lecture class found at the end of the semester that the total point distribution in his class was approximately normal with a mean of 530 and a standard deviation of 80. About what percent scored between 490 and 590? 77.3% 46.5%. 30.9% The 68-95-99.7 rule tells us how to find the middle 68%, 95% or 99.7% of a normal distribution. Suppose we wanted to find numbers A and B, so that the middle 80% of a standard normal distribution lies between A and B, where A is less than B. One of the answers below is NOT true of A and B. Which answer is NOT true? Twenty percent of the distribution lies below A To get the middle 80%, we would have A = -B. B is approximately 1.28.

Explanation / Answer

P(X <x) = 10%

=>

P(Z < x - mean/std) = 0.1

=>

x - 530/ 80 = invnorm(0.1)

=>

x-530 = (-1.282)* 80

x = 427.44

= 428

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