Consider the trash bag problem. Suppose that an independent laboratory has teste
ID: 3263117 • Letter: C
Question
Explanation / Answer
mean = 50.563
n = 36
sigma = 1.61
Here, the null and alternate hypothesis are
H0: mu <= 50
H1: mu > 50
As this is one tailed test, we are concerned with the upper limit. Null hypothesis will be rejected only if the value of mean of sample is greater than this upper limit.
This actually means null hypothesis cannot be rejected for the value between 0 and upper limit.
(a)
For 95% CI, z-value = 1.64
lower limit = 0
upper limit = 50 + 1.64*1.61/sqrt(36) = 50.4401
For 99% CI, z-value = 2.33
lower limit = 0
upper limit = 50 + 2.33*1.61/sqrt(36) = 50.6252
(b)
Using 95%, we reject null hypothesis. This means we are confident enough to confirm the mean is atleast 50 pounds.
(c) Using 99% CI, we fail to reject the null hypothesis. This means we are not confident enough to confirm the mean is at least 50 pounds.
(d) 95% confident that the bag is atleast 50 pounds strong.
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