True/ false and why 1. Because the data is categorical, the correct procedure to

Question

True/ false and why

1. Because the data is categorical, the correct procedure to test whether or not the mean GPAs are equal for Freshmen, Sophomores, Juniors, and Seniors would be a Chi-Square goodness of fit test.

3. In a one-way ANOVA problem, the grand mean is the average of the means of the different treatment groups.

6.Accepting the book notation, in one-way ANOVA, SSA + SSE = SS(total); degrees of freedom treatment + degrees of freedom error = degrees of freedom total; and MSA + MSE = MS(total).

8. In a one-way ANOVA, the variation in the response variable is decomposed into variation within the treatments and variation due to random chance (sampling error).

9. If the null hypothesis in ANOVA is not true, the MSE, a measure of the variability in the data will become large and that will increase the size of the test statistic, making the null hypothesis likely to be rejected.

Explanation / Answer

1 ans) true because if any data is categorical we use chisquare test

3 ans) yes true because the grand mean of all the observations = to the mean of the group means.

6 ans) false because MSA calculated Mean of Sum of All treatment squared errors;

8 ans) true its because suum of squares measures the variability of the observed values around their respectivetreatment means

9 ans) yes true because larger difference between the groups would be reflected

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