Robert Altoff is vice president for engineering for a manufacturer of household
ID: 3266012 • Letter: R
Question
Robert Altoff is vice president for engineering for a manufacturer of household washing machines. As part of new product development, he wishes to determine the optimal length of time for the washing cycle. A part of the development is to study the relationship between the detergent used (four brands) and the length of the washing cycle (18, 20, 22, or 24 minutes). In order to run the experiment, 32 standard household laundry loads (having equal amounts of dirt and the same total weights) are randomly assigned to the 16 detergent-washing cycle combinations. The results (in pounds of dirt removed) are shown below. Cycle Time (min) Detergent Brand 18 20 22 24 A .12 .12 .21 .19 .11 .11 .17 .18 B .14 .15 .18 .20 .10 .14 .17 .18 C .16 .15 .18 .19 .17 .14 .19 .21 D .09 .12 .16 .15 .13 .13 .16 .17 a. Complete an ANOVA table. Use the .05 significance level. (Round SS, MS, p to 3 decimal places and F to 2 decimal places. Leave no cells blank - be certain to enter "0" wherever required.) Source df SS MS F p Cycle Brand Interaction Error Total b-1. Find the cycle mean values. (Round your answers to 3 decimal places.) Cycle Mean 18 Min 20 Min 22 Min 24 Min b-2. Find the brand mean values. (Round your answers to 3 decimal places.) Brand Mean A B C D d. Choose the right option a. For the p-value calculated there is . b. from the values calculated. c. The confidence interval indicate that cycle times of 22 and 24 minutes are to alternatives.
Explanation / Answer
Anova: Two-Factor With Replication SUMMARY 18 20 22 24 Total A Count 2 2 2 2 8 Sum 0.23 0.23 0.38 0.37 1.21 Average 0.115 0.115 0.19 0.185 0.15125 Variance 0.00005 0.00005 0.0008 5E-05 0.001641071 B Count 2 2 2 2 8 Sum 0.24 0.29 0.35 0.38 1.26 Average 0.12 0.145 0.175 0.19 0.1575 Variance 0.0008 5E-05 5E-05 0.0002 0.000992857 C Count 2 2 2 2 8 Sum 0.33 0.29 0.37 0.4 1.39 Average 0.165 0.145 0.185 0.2 0.17375 Variance 5E-05 5E-05 5E-05 0.0002 0.000541071 D Count 2 2 2 2 8 Sum 0.22 0.25 0.32 0.32 1.11 Average 0.11 0.125 0.16 0.16 0.13875 Variance 0.0008 5E-05 0 0.0002 0.000698214 Total Count 8 8 8 8 Sum 1.02 1.06 1.42 1.47 Average 0.1275 0.1325 0.1775 0.18375 Variance 0.000792857 0.00022143 0.000278571 0.000341071 ANOVA Source of Variation SS df MS F P-value F crit Sample 0.005084375 3 0.001694792 7.859903382 0.001904751 3.238871517 Columns 0.020759375 3 0.006919792 32.09178744 5.30647E-07 3.238871517 Interaction 0.002903125 9 0.000322569 1.495974235 0.230961204 2.537666539 Within 0.00345 16 0.000215625 Total 0.032196875 31
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.