10)_ 10) The hst statistic in a twiolaik-d test is ,-195 A)00612, bst the null h
ID: 3266608 • Letter: 1
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10)_ 10) The hst statistic in a twiolaik-d test is ,-195 A)00612, bst the null hypothesis 000k oset the wull hypothess B)0512, (ad to repot the null hypothesis 0)09744, fall to rejpct the null hypothesis Find the vahne of the test statietic using Find the value ef the test statistie s using PD 1) 11) A claim is made that the proportion of children who play sports is less than 0.5, and the sample statistics indode n-1320 subpects with 30% saying that they play a spxrt A)-143 6) 148 C)2966 D)-2966 17) 12) The claim ts that the proportion of accidental deaths of the elderly attributable to residential falls is more than 0 10, and the sample statistics include n-N0 deaths of the elderly with 15% of them attributable to rosidential falls A)-396 B)3% C)-471 D) 4.71 Provide an appropeiate response. 13) The business college commputing center wants to determine the proportion of business students who 13)_ have personal computers (PC-s) at homo If the proportion exceeds 30%, then the lab will scale back a proposed enlargement of its facilitios Suppose 250 business shidents were randomly sampled and 75 have PC's at home. Find the rejction region for this teut using-005 A) Reject Ho if-1645 Rejet Ho if z>1645 B) Reject Ho if z-1645 D) Reject Ho if 1.,96 or z-1.96. 14) The business college computing center wants to determine the proportion of business students who 14) 14) have personal computers (PCs) at home lf the Pryor tson differs from 35%, then thc lab will modify a proposed enlargement of its facilities Suppose a hypothesis test is conducted and the test statistic is 26 Find the P-value for a two-tailed test of hypothess A) 0 0004 B) 0.4953 C0 4906 D) 00047 15) 15) If the p-value is less than a in a two-tail test, A) the null hypothesis should not be rejected B) a one-lail test should be used C) no conclusion shouild be reached D) the null hypothesis should be rjected 16) A manager of the credit department for an oil company would like to determine whether the mean 16) monthly balance of credit card holders is equal to $75 An auditor solects a rankdom sample of 100 accounts and finds that the mean owed is $83 40 with a sample standard deviation of $2365. If you wanted to test whether the mean balance is different from $75 and decided to reject the null hypothesis, what conclusion could you reach? A) There is evidence that the mean balance is $75 B) There is not evidence that the mean balance is $75 Q There is evidence that the mean balance is not $75, D) There is not evidence that the mean balance is not $7sExplanation / Answer
Solution:-
11) A) - 14.53
State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.
Null hypothesis: P > 0.50
Alternative hypothesis: P < 0.50
Note that these hypotheses constitute a one-tailed test. The null hypothesis will be rejected only if the sample proportion is too small.
Formulate an analysis plan. For this analysis, the significance level is 0.05. The test method, shown in the next section, is a one-sample z-test.
Analyze sample data. Using sample data, we calculate the standard deviation () and compute the z-score test statistic (z).
= sqrt[ P * ( 1 - P ) / n ]
= 0.01376
z = (p - P) /
z = - 14.53
12) (D) 4.71
State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.
Null hypothesis: P < 0.10
Alternative hypothesis: P > 0.10
Note that these hypotheses constitute a one-tailed test. The null hypothesis will be rejected only if the sample proportion is too small.
Formulate an analysis plan. For this analysis, the significance level is 0.05. The test method, shown in the next section, is a one-sample z-test.
Analyze sample data. Using sample data, we calculate the standard deviation () and compute the z-score test statistic (z).
= sqrt[ P * ( 1 - P ) / n ]
= 0.01061
z = (p - P) /
z = 4.713
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