both pictures are one problem 2. For the 500 women with GDM that you sampled for
ID: 3269009 • Letter: B
Question
both pictures are one problem
Explanation / Answer
Question 2
Part a
Here, we have to use two sample t test for the population mean. The null and alternative hypotheses for this test are given as below:
Null hypothesis: H0: There is no any statistically significant difference for the average glucose prior to pregnancy for overweight/obese women and normal weight women.
Alternative hypothesis: Ha: There is a statistically significant difference for the average glucose prior to pregnancy for overweight/obese women and normal weight women.
H0: µ1 = µ2 versus Ha: µ1 µ2
This is a two tailed test.
Test statistic formula is given as below:
t = (X1bar – X2bar) / sqrt[(S1^2/N1)+(S2^2/N2)]
We are given
X1bar = 102.1
X2bar = 98.8
S1 = 20
S2 = 16
N1 = 500*0.70 = 350
N2 = 500*0.30 = 150
Level of significance = alpha = = 0.05 = 5%
Degrees of freedom = 500 – 2 = 498
Critical values = -1.9647 and 1.9647
Test statistic = t = (102.1 - 98.8) / sqrt((20^2/350)+(16^2/150))
Test statistic = t = 1.954914621
P-value = 0.0512
= 0.05
P-value >
So, we do not reject the null hypothesis that there is no any statistically significant difference for the average glucose prior to pregnancy for overweight/obese women and normal weight women.
There is insufficient evidence to conclude that there is a statistically significant difference for the average glucose prior to pregnancy for overweight/obese women and normal weight women.
Part b
Here, we have to use two sample t test for the population mean. The null and alternative hypotheses for this test are given as below:
Null hypothesis: H0: There is no any statistically significant difference for the average glucose prior to pregnancy for overweight/obese women and normal weight women.
Alternative hypothesis: Ha: The average glucose prior to pregnancy for overweight/obese women is higher than average glucose prior to pregnancy for normal weight women.
H0: µ1 = µ2 versus Ha: µ1 > µ2
This is a one tailed test. This is an upper tailed test. This is right tailed test.
Test statistic formula is given as below:
t = (X1bar – X2bar) / sqrt[(S1^2/N1)+(S2^2/N2)]
We are given
X1bar = 102.1
X2bar = 98.8
S1 = 20
S2 = 16
N1 = 500*0.70 = 350
N2 = 500*0.30 = 150
Level of significance = alpha = = 0.05 = 5%
Degrees of freedom = 500 – 2 = 498
Upper Critical values = 1.6479
Test statistic = t = (102.1 - 98.8) / sqrt((20^2/350)+(16^2/150))
Test statistic = t = 1.954914621
P-value = 0.0256
= 0.05
P-value <
So, we reject the null hypothesis that there is no any statistically significant difference for the average glucose prior to pregnancy for overweight/obese women and normal weight women.
There is sufficient evidence to conclude that the average glucose prior to pregnancy for overweight/obese women is higher than average glucose prior to pregnancy for normal weight women.
Part c
Second analysis b had greater power because the p-value for part b is less than part a.
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