MATH 115-A02 Summer 2017 Homework: HW #10: Sec 12.1-12.3 Score: 0.5 of 1 pt 12.3
ID: 3269427 • Letter: M
Question
MATH 115-A02 Summer 2017 Homework: HW #10: Sec 12.1-12.3 Score: 0.5 of 1 pt 12.3.33 36 of 38 (38 complete) Subtract 10 from each item in the given sample, and compute the mean and standard deviation of the new sample. 48, 32, 37, 14, 22, 33, 37 The mean of the new sample is 21.86 (Simplify your answer. Type an integer or decimal rounded to the nearest hundredth as needed.) The standard deviation of the new sample is 11.04 (Simplify your answer. Type an integer or decimal rounded to the nearest hundredth as needed.)Explanation / Answer
1)
(48 - 10) = 38 , ( 32 -10) = 22 , ( 37 -10) = 27 , ( 14 -10) = 10 , ( 22 -10) = 12 , ( 33 -10) = 23 , ( 37 -10) = 27
mean = ( 38 + 22 + 27 + 10 + 12 + 23 + 27) / 7 = 22.714
Standard deviation = 9.552
2)
mean = (23+42+35+40+26+32)/6 = 33
standard deviation = (23-33)^2 + (42 - 23)^2 + ( 35 - 33)^2 + ( 40-33)^2 + ( 26-33)^2 + ( 32- 33)^2 / 5
Standard deviation = 7.536
The mean of the new data sample is = 5 * 33 = 165
The standard deviation of the new data sample is = 5 * 7.536 = 37.68
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