Quiz: Week 7 Quiz Time Remaining: 01 09 53 Submit Quc This Question: 4 pts 14 of
ID: 3270179 • Letter: Q
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Quiz: Week 7 Quiz Time Remaining: 01 09 53 Submit Quc This Question: 4 pts 14 of 19 (2 complete) This Quiz: 60 pts possibie In a survey of a group of men, the heights in the 20-29 age group parts (a) through (d) below were normally distributed, with a mean of 676 inches and a standard deviation of 2 0 inches A study partiopant is randomy selected Complete (a) Find the probability that a study participant has a height that is less than 68 inches probabifity that the study participant selected at random ts less than 68 inches tallis(Round to tour decimal b) Find the probability that a study particpant has a height that is between 68 and 71 inches The probability that the study participant selected at random is between 68 and 71 nces ta (c) Find the probabety that a study participant nas a height that is more than 71 inches The probabaty that the stuty participant selected at random is more than 71 inches ta s (Round to four decimal places as needed) (d) identify any unusual events Explain your reasoning Choose the correct answer below h places as needed ) A None of the events are unusual because all the probablines are greater than 0.05 B. The events in parts (a) and (b) are unusual because its probabities are less than 0 06 C. The event in part (c) is unusual because its probability is less than 0 06 Click to select your answers) °Type here to search 2s20 8 9 0Explanation / Answer
given
we know
z =x^-mean / standard deviation so
a)Find the probability that his height is less than 68 inches
z(68) = (68-67.6)/2= 0.2
from standard z table we have the value of 0.2 is
P(x < 0.2) = P(z < 0.2) = 0.5793
b) FInd the probability that the height is between 68 and 71 inches
z(71) = (71-67.6)/2 = 1.7
P(68< x <71) = P(0.2< z <1.7)=
0.9554-0.5793=0.3761
c)
Find the probability that the height is more than 71 inches
P(x > 71) = P(z > 1.7) =1-0.9554=0.0446
d)option c
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