Construct one table that includes relative frequencies based on the frequency di

Question

Construct one table that includes relative frequencies based on the frequency distribution shown, then compare the amounts of tar in notfiltered and filtered cigarette. Do the cigarette filters appear to be effective? Complete the relative frequency table below. Do cigarette filters appear to be effective? No, because the relative frequencies for each are not substantially different. No, because the relative frequency of the higher tar classes is greater for filtered cigarettes. Yes, because the relative frequency of the higher tar classes is greater for nonfiltered cigarettes. This cannot be determined.

Explanation / Answer

The total frequency for nonfiltered cigarettes is computed as: 1 + 0 + 16 + 7 +1 = 25

The total frequency for filtered cigarettes is computed as: 2 + 1 + 5 + 17 = 25

The relative frequencies are computed by dividing the frequencies by 25 ( which is the total frequency ) Therefore now the relative frequencies are computed as;

Clearly the filter is effective because the relative frequencies are clearly higher for higher tar classes in nonfiltered cigarettes.

Tar (mg) Frequency ( Nonfiltered ) Frequency ( Filtered ) Relative Frequency (Nonfiltered) Relative Frequency (Filtered ) 7-10 0 1 0 1/25 = 0.04 11-14 0 2 0 2/25 = 0.08 15-18 2 7 2/25 = 0.08 7/25 = 0.28 19-22 0 15 0 15/25 = 0.6 23-26 14 0 14/25 = 0.56 0 27-30 6 0 6/25 = 0.24 0 31-34 3 0 3/25 = 0.12 0

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